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FlexiSign 10.0.1 Serial Key

This is the full version of SAi FlexiSign 10.0.1 Serial Number Key. Latest Features: – redesigned user interface. .
FlexiSign-10.0.1+crack.zip SERIAL number. Flexisign pro 10 serial key is a Multilingual tool specially designed to create Signatures.Q:

How to factor an expression containing inversion?

I have an expression like this
$$\lim_{n\to \infty} \frac{\sum_{k=0}^{n-1} k^2}{\sum_{k=0}^{n-1} k} = \frac{n(n+1)}{2n(n+1)} = \frac{2}{2}$$
I should factor out the $1/2$, and $\frac{1}{2}$ appears.
I have tried to solve it by
$(a+b)^2 = a^2+b^2+2ab$
However, I don’t know how to continue. I can see the signs come out but I couldn’t get the coefficients.

A:

It is indeed correct that $$(a+b)^2=(a^2+2ab)+b^2$$
and therefore,
$$
\begin{align}
(a+b)^2&=a^2+b^2+2ab\\
&=a^2+b^2+2ab\\
&=a^2+b^2+2ab\tag{1}\\
&=(a+b)^2\tag{2}
\end{align}
$$
but I would be careful about using $(2)$ in this problem. If we already know the identity $(1)$ then there is no reason to evaluate $(2)$ as well.
Another way to see this is to note that the identity
$$
(a+b)^2=(a^2+2ab)+b^2
$$
also allows us to factor out $a^2+b^2$ from the LHS of this identity.

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